d/(dp)((t)(p+n^2a))

解答

\frac{d}{d p} ((t) (p + n^{2} a))

t

求解步骤

\frac{d}{d p} ((t) (p + n^{2} a))

将

a, n, t

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= t \frac{d}{d p} (p + n^{2} a)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= t (\frac{d p}{d p} + \frac{d}{d p} (n^{2} a))

\frac{d p}{d p} = 1

\frac{d}{d p} (n^{2} a) = 0

= t (1 + 0)

化简

= t

e x p an d (f \circ g) 3 (3 x^{2} + 7) + 5 (3 x^{2} + 7)

e x p an d x^{2} - \frac{5}{3} x

e x p an d \frac{2 ( x - 1 ) ^{2} ( x - 3 )}{( x + 2 ) ( x + 7 )}

e x p an d f^{'} (x) (45 - p (x))

\frac{d}{d x} ((2) (x^{2} (6 - x)^{3}))