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Popular >

d/(d{x)}(({z})({x}^2+2{y}^2+3{z}^2-1))

Solution

\frac{d}{d x} ((z) (x^{2} + 2 y^{2} + 3 z^{2} - 1))

Solution

2 z x

Solution steps

\frac{d}{d x} ((z) (x^{2} + 2 y^{2} + 3 z^{2} - 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{d}{d x} (x^{2} + 2 y^{2} + 3 z^{2} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 y^{2}) + \frac{d}{d x} (3 z^{2}) - \frac{d}{d x} (1))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 y^{2}) = 0

\frac{d}{d x} (3 z^{2}) = 0

\frac{d}{d x} (1) = 0

= z (2 x + 0 + 0 - 0)

Simplify

= 2 z x

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(({z})({x}^2+2{y}^2+3{z}^2-1)) ?
The d/(d{x)}(({z})({x}^2+2{y}^2+3{z}^2-1)) is 2{z}{x}
What is the first d/(d{x)}(({z})({x}^2+2{y}^2+3{z}^2-1)) ?
The first d/(d{x)}(({z})({x}^2+2{y}^2+3{z}^2-1)) is 2{z}{x}