展开 (2e^{2r}sin(3θ))(s-2t)

解答

展开

(2 e^{2 r} sin (3 θ)) (s - 2 t)

2 e^{2 r} s sin (3 θ) - 4 e^{2 r} t sin (3 θ)

求解步骤

(2 e^{2 r} sin (3 θ)) (s - 2 t)

使用分配律:

a (b - c) = ab - a c

a = (2 e^{2 r} sin (3 θ)), b = s, c = 2 t

= (2 e^{2 r} sin (3 θ)) s - (2 e^{2 r} sin (3 θ)) \cdot 2 t

= s (2 e^{2 r} sin (3 θ)) - 2 t (2 e^{2 r} sin (3 θ))

化简

s (2 e^{2 r} sin (3 θ)) - 2 t (2 e^{2 r} sin (3 θ)) : 2 e^{2 r} s sin (3 θ) - 4 e^{2 r} t sin (3 θ)

= 2 e^{2 r} s sin (3 θ) - 4 e^{2 r} t sin (3 θ)

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