vereinfachen (Ae^{imθ}+Be^{-imθ})^2

Lösung

vereinfachen

(A e^{im θ} + B e^{- im θ})^{2}

(A (cos (m θ) + i sin (m θ)) + B (cos (m θ) - i sin (m θ)))^{2}

Schritte zur Lösung

(A e^{im θ} + B e^{- im θ})^{2}

e^{im θ} = cos (m θ) + i sin (m θ)

= (A (cos (m θ) + i sin (m θ)) + e^{- im θ} B)^{2}

e^{- im θ} = cos (m θ) - i sin (m θ)

= (A (cos (m θ) + i sin (m θ)) + B (cos (m θ) - i sin (m θ)))^{2}

s im pl i f y \frac{1}{4 ( 8 - a - b - y ) ^{2}}

e x p an d a sin (\frac{π}{4} (k + 1)) + b cos (\frac{π}{4} (k + 1))

e x p an d - 3 (8 e^{- 3 x} - 2 cos (2 x) + 3 sin (2 x)) + 13 sin (2 t)

e x p an d \frac{( 2 x - 7 ) ( x + 1 )}{x + 5}

e x p an d d x (\frac{1}{15} arctan (\frac{x}{5}) + c)