展开 (-3/2 x+b)^2

解答

展开

(- \frac{3}{2} x + b)^{2}

\frac{9 x ^{2} - 12 b x + 4 b ^{2}}{4}

求解步骤

(- \frac{3}{2} x + b)^{2}

使用完全平方公式:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(- \frac{3}{2} x + b)^{2} = (- \frac{3}{2} x)^{2} + 2 (- \frac{3}{2} x) b + b^{2}

= (- \frac{3}{2} x)^{2} + 2 (- \frac{3}{2} x) b + b^{2}

化简

(- \frac{3}{2} x)^{2} + 2 (- \frac{3}{2} x) b + b^{2} : \frac{9 x ^{2} - 12 b x + 4 b ^{2}}{4}

= \frac{9 x ^{2} - 12 b x + 4 b ^{2}}{4}

\frac{d ^{2}}{d x ^{2}} ((y (t, x)) (t^{3} + t))

e x p an d (y^{3} + 5 x y^{4} - 2 x) d x + (3 x y^{2} + 20 x^{2} y^{3}) d x

e x p an d (y^{3} + 5 x y^{4} - 2 x) d x + (3 x y^{2} + 20 x^{2} y^{3}) d y

e x p an d (x) d x + (y - 2 x) d y

e x p an d \frac{x ( x ^{\frac{1}{3}} - x ^{\frac{3}{2}} )}{x ^{\frac{2}{3}} - x ^{\frac{3}{2}}}