展开-(2x+1)sin(x^2+x)

解答

展开

- (2 x + 1) sin (x^{2} + x)

- 2 x sin (x^{2} + x) - sin (x^{2} + x)

求解步骤

- (2 x + 1) sin (x^{2} + x)

= - sin (x^{2} + x) (2 x + 1)

使用分配律:

a (b + c) = ab + a c

- sin (x^{2} + x) (2 x + 1) = - sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1

= - sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1

化简

- sin (x^{2} + x) \cdot 2 x - sin (x^{2} + x) \cdot 1 : - 2 x sin (x^{2} + x) - sin (x^{2} + x)

= - 2 x sin (x^{2} + x) - sin (x^{2} + x)

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e x p an d \frac{5 ( 6 - x ) ^{2}}{3}

e x p an d R (- 3, 2, - 5) S (- 5, 1, - 3)

\frac{d ^{3}}{d x ^{3}} ((y) (4 x^{5} - 3 x^{4} + 2 x))