化简 sqrt(4+(6t^2+10t)^2)

解答

化简

4 + (6 t^{2} + 10 t)^{2}

2 1 + 9 t^{4} + 30 t^{3} + 25 t^{2}

求解步骤

4 + (6 t^{2} + 10 t)^{2}

因式分解

4 + (6 t^{2} + 10 t)^{2} : 4 (1 + 9 t^{4} + 30 t^{3} + 25 t^{2})

= 4 (1 + 9 t^{4} + 30 t^{3} + 25 t^{2})

使用根式运算法则:

ab = a b,

假定

a \geq 0, b \geq 0

4 (1 + 9 t^{4} + 30 t^{3} + 25 t^{2}) = 4 1 + 9 t^{4} + 30 t^{3} + 25 t^{2}

= 4 1 + 9 t^{4} + 30 t^{3} + 25 t^{2}

4 = 2

= 2 1 + 9 t^{4} + 30 t^{3} + 25 t^{2}

ma g ni t u d e (21 - 1)

e x p an d \frac{d}{d x} (ln (x) y) + ln (1 - x) \cdot (n - y)

e x p an d \frac{6 x ^{2} - 6 x + 6 x h - 3 h - 8}{( 2 x - 1 ) ( 2 x + 2 h - 1 )}

e x p an d \frac{1}{( 9 + 4 x ^{2} )}

e x p an d (8.22 cos (t) - 3.69)^{2}