vereinfachen (2sqrt(x^3+6x)+1)^2

Lösung

vereinfachen

(2 x^{3} + 6 x + 1)^{2}

4 (x^{3} + 6 x) + 4 x^{3} + 6 x + 1

Schritte zur Lösung

(2 x^{3} + 6 x + 1)^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 x^{3} + 6 x + 1)^{2} = (2 x^{3} + 6 x)^{2} + 2 \cdot 2 x^{3} + 6 x \cdot 1 + 1^{2}

= (2 x^{3} + 6 x)^{2} + 2 \cdot 2 x^{3} + 6 x \cdot 1 + 1^{2}

(2 x^{3} + 6 x)^{2} = 4 (x^{3} + 6 x)

2 \cdot 2 x^{3} + 6 x \cdot 1 = 4 x^{3} + 6 x

1^{2} = 1

= 4 (x^{3} + 6 x) + 4 x^{3} + 6 x + 1

e x p an d \frac{2 s}{( s - 1 ) ( s ^{2} + 4 )}

\frac{d}{d x} ((t) (e^{t} (sin (t) + cos (t))))

e x p an d \frac{1 + 10}{2}

e x p an d (x - \frac{1}{4}) (x - (-) \frac{2}{3})

e x p an d x + 3 2^{2}