展开 1/608-1/44+37/30*2

解答

展开

\frac{1}{60} \cdot 8 - \frac{1}{4} \cdot 4 + \frac{37}{30} \cdot 2

\frac{8}{5}

十进制

1.6

求解步骤

\frac{1}{60} \cdot 8 - \frac{1}{4} \cdot 4 + \frac{37}{30} \cdot 2

\frac{1}{60} \cdot 8 = \frac{2}{15}

\frac{1}{4} \cdot 4 = 1

\frac{37}{30} \cdot 2 = \frac{37}{15}

= \frac{2}{15} - 1 + \frac{37}{15}

对同类项分组

= \frac{2}{15} + \frac{37}{15} - 1

合并分式

\frac{2}{15} + \frac{37}{15} : \frac{13}{5}

= \frac{13}{5} - 1

将项转换为分式:

1 = \frac{1 \cdot 5}{5}

= - \frac{1 \cdot 5}{5} + \frac{13}{5}

因为分母相等，所以合并分式:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- 1 \cdot 5 + 13}{5}

- 1 \cdot 5 + 13 = 8

= \frac{8}{5}

e x p an d ((2 x^{2} y - 2 y^{2} + 2 x y) d x + (x^{2} - 2 y) d y = 0) e^{2 x}

e x p an d \frac{( x - 9 ) ( x + 1 ) ( x + 6 )}{( x + 8 ) ( x + 4 )}

e x p an d 4 (x - 1) (x + 1) (x^{2} + 1) (x^{4} + 1) + 1

s im pl i f y (a - b 2) (a + b 2)

e x p an d (\frac{t ^{2}}{8} - \frac{t ^{3}}{12})^{2}