What is expand a(cos(x+sin(x))=1-i) ?

The solution to expand a(cos(x+sin(x))=1-i) is acos(x+sin(x))=1-ia

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expand a(cos(x+sin(x))=1-i)

expand

a (cos (x + sin (x)) = 1 - i)

a cos (x + sin (x)) = 1 - ia

Solution steps

a (cos (x + sin (x)) = 1 - i)

= a (1 = cos (x + sin (x)) - i)

Apply the distributive law:

a (b - c) = ab - a c

a = a, b = cos (x + sin (x)) = 1, c = i

a cos (x + sin (x)) = 1 - ai

a cos (x + sin (x)) = 1 - ia

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(x - π) \cdot (x^{2} + 2)

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e^{- x} (1 + x) \frac{d y}{d x} - e^{- x} x y

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What is expand a(cos(x+sin(x))=1-i) ?
The solution to expand a(cos(x+sin(x))=1-i) is acos(x+sin(x))=1-ia