erweitern (4x(x+k))/((2x+k)(kx+k^2+2x))

Lösung

erweitern

\frac{4 x ( x + k )}{( 2 x + k ) ( k x + k ^{2} + 2 x )}

\frac{4 x ^{2} + 4 k x}{2 k x ^{2} + 4 x ^{2} + 3 k ^{2} x + 2 k x + k ^{3}}

Schritte zur Lösung

\frac{4 x ( x + k )}{( 2 x + k ) ( k x + k ^{2} + 2 x )}

Multipliziere aus

(2 x + k) (k x + k^{2} + 2 x) : 2 k x^{2} + 4 x^{2} + 3 k^{2} x + 2 k x + k^{3}

= \frac{4 x ( x + k )}{2 k x ^{2} + 4 x ^{2} + 3 k ^{2} x + 2 k x + k ^{3}}

Multipliziere aus

4 x (x + k) : 4 x^{2} + 4 k x

= \frac{4 x ^{2} + 4 k x}{2 k x ^{2} + 4 x ^{2} + 3 k ^{2} x + 2 k x + k ^{3}}

e x p an d (9 e f + 2 f) (e - 5)

e x p an d x - x H (x - 2) + 2 H (x \cdot 2)

e x p an d \frac{3 + 2 s}{( s + 1 ) ( 2 s + 1 ) ( s - 1 ) ( s + 2 )}

e x p an d \frac{4 x ^{2} ln ( 3 x ^{2} + 5 ) + 6 ( x ^{4} + 2 )}{( 3 x ^{2} + 5 )}

e x p an d - 3 + (3 (1 - e)) e^{x}