化简 (2+sin(θ))^2+cos^2(θ)

解答

化简

(2 + sin (θ))^{2} + cos^{2} (θ)

4 sin (θ) + 5

求解步骤

(2 + sin (θ))^{2} + cos^{2} (θ)

展开

(2 + sin (θ))^{2} : 4 + 4 sin (θ) + sin^{2} (θ)

= 4 + 4 sin (θ) + sin^{2} (θ) + cos^{2} (θ)

使用毕达哥拉斯恒等式:

cos^{2} (x) + sin^{2} (x) = 1

= 4 sin (θ) + 4 + 1

数字相加:

4 + 1 = 5

= 4 sin (θ) + 5

e x p an d (3 - \frac{3}{2 y})^{2}

e x p an d (10 b - \frac{4}{3} y)^{2}

e x p an d 4 (e^{x} + e^{x} x)

e x p an d 5 (\frac{3}{7} u - \frac{3}{13} v^{2})^{2}

e x p an d \frac{( 3 + 4 x ) ^{3}}{( 4 - 3 x ) ^{4}}