erweitern (x+2)(x-2)[x-2/(x^2-4)+1/(x+2)= 1/(x-2)]

Lösung

erweitern

(x + 2) (x - 2) [x - \frac{2}{x ^{2} - 4} + \frac{1}{x + 2} = \frac{1}{x - 2}]

x^{2} [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}] - 4 [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}]

Schritte zur Lösung

(x + 2) (x - 2) [x - \frac{2}{x ^{2} - 4} + \frac{1}{x + 2} = \frac{1}{x - 2}]

= (x + 2) (x - 2) [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}]

Multipliziere aus

(x + 2) (x - 2) : x^{2} - 4

= [x - \frac{2}{x ^{2} - 4} + \frac{1}{x + 2} = \frac{1}{x - 2}] (x^{2} - 4)

Multipliziere aus

[x - \frac{2}{x ^{2} - 4} + \frac{1}{x + 2} = \frac{1}{x - 2}] (x^{2} - 4) : x^{2} [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}] - 4 [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}]

= x^{2} [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}] - 4 [x - \frac{2}{x ^{2} - 4} + = \frac{1}{x + 2} \cdot \frac{1}{x - 2}]

e x p an d (x - 9) x

e x p an d \frac{( 2 x + 1 ) ^{3} ( 2 x - 3 ) ^{3}}{x ^{6}}

e x p an d (- 1, 3) y (3, - 8) p u n t o (9, 6)

e x p an d (2 y y^{'} (x) = 20 x^{3} - 2 x) \frac{1}{2}

e x p an d (x + 2 y = 1, 3) (x - 2 y = - 7)