化简 6(7d+1/2)

解答

化简

6 (7 d + \frac{1}{2})

42 d + 3

求解步骤

6 (7 d + \frac{1}{2})

合并

7 d + \frac{1}{2} : \frac{14 d + 1}{2}

= 6 \cdot \frac{14 d + 1}{2}

使用分式法则:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{6 ( 14 d + 1 )}{2}

数字相除:

\frac{6}{2} = 3

= 3 (14 d + 1)

展开

3 (14 d + 1) : 42 d + 3

= 42 d + 3

e x p an d \frac{sin ^{2} ( x )}{( 1 + cos ( x ) ) ^{2}}

e x p an d - \frac{1}{2} x^{2} + 2 x - \frac{3}{2} + \frac{1}{3} (x - 1)^{3}

e x p an d 3 e^{3 x} x^{3} ln (x + 1) (x + 1)

e x p an d - 3 (x - 1 = - 4) x + 20

e x p an d (- 1 - 37)^{3}