展开 2pi(e^2-1)

解答

展开

2 π (e^{2} - 1)

2 e^{2} π - 2 π

十进制

40.14362 \dots

求解步骤

2 π (e^{2} - 1)

使用分配律:

a (b - c) = ab - a c

a = 2 π, b = e^{2}, c = 1

= 2 π e^{2} - 2 π 1

= 2 e^{2} π - 2 \cdot 1 π

数字相乘:

2 \cdot 1 = 2

= 2 e^{2} π - 2 π

s im pl i f y g (- sin (\frac{π}{12}) - (0.12) cos (\frac{π}{12}))

e x p an d \frac{50 ( 3 11 - 1 )}{49}

e x p an d 6 (π^{9999} - 1)

e x p an d (x^{2} + 1) y^{''} (x) - x y^{'} (x) + y

s im pl i f y (1 + ρ \cdot e^{i ψ})^{2}