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simplificar (2.45-1)(8.854210^{-12})(1210^3)

Solución

simplificar

(2.45 - 1) (8.8542 \cdot 1 0^{- 12}) (12 \cdot 1 0^{3})

\frac{3851577}{25 \cdot 1 0 ^{12}}

Notación decimal

1.54063 E - 7

Pasos de solución

(2.45 - 1) (8.8542 \cdot 1 0^{- 12}) (12 \cdot 1 0^{3})

Restar:

2.45 - 1 = 1.45

= 1.45 \cdot 8.8542 \cdot 1 0^{- 12} \cdot 12 \cdot 1 0^{3}

Aplicar las leyes de los exponentes:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 12} = \frac{1}{1 0 ^{12}}

= 1.45 \cdot 8.8542 \cdot \frac{1}{1 0 ^{12}} \cdot 12 \cdot 1 0^{3}

1 0^{3} = 1000

= 1.45 \cdot 8.8542 \cdot \frac{1}{1 0 ^{12}} \cdot 12 \cdot 1000

Multiplicar los numeros:

1.45 \cdot 8.8542 \cdot 12 \cdot 1000 = 154063.08

= 154063.08 \cdot \frac{1}{1 0 ^{12}}

154063.08 \cdot \frac{1}{1 0 ^{12}} = \frac{154063.08}{1 0 ^{12}}

= \frac{154063.08}{1 0 ^{12}}

\frac{154063.08}{1 0 ^{12}} = \frac{15406308}{100 \cdot 1 0 ^{12}}

= \frac{15406308}{100 \cdot 1 0 ^{12}}

Descomponer el número en factores primos:

15406308 = 4 \cdot 3851577

= \frac{4 \cdot 3851577}{100 \cdot 1 0 ^{12}}

Descomponer el número en factores primos:

100 = 4 \cdot 25

= \frac{4 \cdot 3851577}{4 \cdot 25 \cdot 1 0 ^{12}}

Eliminar los terminos comunes:

4

= \frac{3851577}{25 \cdot 1 0 ^{12}}

2 e^{x} \cdot 2 e^{x}

(3 x^{2}) (4 x^{5})

(\frac{10}{3})^{3} \times 0. 3^{- 1}

(5 x)^{2}

b^{3} x^{3}