de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Algebra >

vereinfachen (\sqrt[3]{(12w)})^5

Lösung

vereinfachen

(3 (12 w))^{5}

Lösung

12 3 1 2^{2} 3 w^{5}

Schritte zur Lösung

(3 12 w)^{5}

Apply rule:

(a) = a

(12 w) = 12 w

= (3 12 w)^{5}

Wende Exponentenregel an:

a^{b + c} = a^{b} \cdot a^{c}

(3 12 w)^{3 + 2} = (3 12 w)^{3} (3 12 w)^{2}

= (3 12 w)^{3} (3 12 w)^{2}

Wende Exponentenregel an:

(n a)^{n} = a,

angenommen

n i s o dd or a \geq 0

(3 12 w)^{3} = 12 w

= 12 w (3 12 w)^{2}

(3 12 w)^{2} = 1 2^{\frac{2}{3}} (3 w)^{2}

= 12 \cdot 1 2^{\frac{2}{3}} w (3 w)^{2}

Wende Exponentenregel an:

a^{b} \cdot a^{c} = a^{b + c}

12 \cdot 1 2^{\frac{2}{3}} = 1 2^{1 + \frac{2}{3}}

= w \cdot 1 2^{1 + \frac{2}{3}} (3 w)^{2}

1 2^{1 + \frac{2}{3}} = 12 \cdot 1 2^{\frac{2}{3}}

= 12 \cdot 1 2^{\frac{2}{3}} w (3 w)^{2}

= 1 2^{\frac{2}{3}} \cdot 12 w (3 w)^{2}

Vereinfache

w (3 w)^{2} : w^{\frac{5}{3}}

= 1 2^{\frac{2}{3}} \cdot 12 w^{\frac{5}{3}}

1 2^{\frac{2}{3}} \cdot 12 = 1 2^{\frac{5}{3}}

= 1 2^{\frac{5}{3}} w^{\frac{5}{3}}

1 2^{\frac{5}{3}} = 12 \cdot 1 2^{\frac{2}{3}}

= 12 \cdot 1 2^{\frac{2}{3}} w^{\frac{5}{3}}

1 2^{\frac{2}{3}} = 3 1 2^{2}

= 12 3 1 2^{2} 3 w^{5}

w^{\frac{5}{3}} = 3 w^{5}

= 12 3 1 2^{2} 3 w^{5}

Beliebte Beispiele

vereinfachen (\sqrt[3]{9})/(\sqrt[3]{x^2)}

s im pl i f y \frac{3 9}{3 x ^{2}}

(d^2)/(dx^2)((y)(e^{-3x}))

\frac{d ^{2}}{d x ^{2}} ((y) (e^{- 3 x}))

vereinfachen e^{-0.00386}

s im pl i f y e^{- 0.00386}

vereinfachen e^{-5t}t^2sin(3t)

s im pl i f y e^{- 5 t} t^{2} sin (3 t)

vereinfachen (e^x)/(e^2)

s im pl i f y \frac{e ^{x}}{e ^{2}}