What is 4log_{3}(2x-1)-1/2 log_{3}((x+1)^2) ?

The solution to 4log_{3}(2x-1)-1/2 log_{3}((x+1)^2) is 4log_{3}(2x-1)-log_{3}(x+1)

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simplify 4log_{3}(2x-1)-1/2 log_{3}((x+1)^2)

simplify

4 lo g_{3} (2 x - 1) - \frac{1}{2} lo g_{3} ((x + 1)^{2})

4 lo g_{3} (2 x - 1) - lo g_{3} (x + 1)

Solution steps

4 lo g_{3} (2 x - 1) - \frac{1}{2} lo g_{3} ((x + 1)^{2})

Simplify

\frac{1}{2} lo g_{3} ((x + 1)^{2}) : lo g_{3} (x + 1)

= 4 lo g_{3} (2 x - 1) - lo g_{3} (x + 1)

lo g_{10} (\frac{x ^{3}}{y ^{2}})

lo g_{10} (3 x + 4) - lo g_{10} (x)

3 ln (x) - 2 ln (y)

3 ln (x) + 5 ln (y) - 2 ln (z)

ln (\frac{e x ^{2}}{x + 1})

What is 4log_{3}(2x-1)-1/2 log_{3}((x+1)^2) ?
The solution to 4log_{3}(2x-1)-1/2 log_{3}((x+1)^2) is 4log_{3}(2x-1)-log_{3}(x+1)