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受欢迎的代数 >

6q^2+3q=5q^2-2q+14

解答

6 q^{2} + 3 q = 5 q^{2} - 2 q + 14

解答

q = - 7, q = 2

求解步骤

6 q^{2} + 3 q = 5 q^{2} - 2 q + 14

交换两边

5 q^{2} - 2 q + 14 = 6 q^{2} + 3 q

将

3 q

para o lado esquerdo

5 q^{2} - 5 q + 14 = 6 q^{2}

将

6 q^{2}

para o lado esquerdo

- q^{2} - 5 q + 14 = 0

使用求根公式求解

q_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 14}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 14 = 9

q_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 ( - 1 )}

将解分隔开

q_{1} = \frac{- ( - 5 ) + 9}{2 ( - 1 )}, q_{2} = \frac{- ( - 5 ) - 9}{2 ( - 1 )}

q = \frac{- ( - 5 ) + 9}{2 ( - 1 )} : - 7

q = \frac{- ( - 5 ) - 9}{2 ( - 1 )} : 2

二次方程组的解是:

q = - 7, q = 2

作图

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