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受欢迎的代数 >

7610^{-12}s^2+3010^{-4}s+820=0

解答

76 \cdot 1 0^{- 12} s^{2} + 30 \cdot 1 0^{- 4} s + 820 = 0

解答

s = \frac{125000000 ( 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}, s = \frac{125000000 ( - 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}

+1

十进制

s = - 275252.68908 \dots, s = - 39198431.52144 \dots

求解步骤

76 \cdot 1 0^{- 12} s^{2} + 30 \cdot 1 0^{- 4} s + 820 = 0

展开

76 \cdot 1 0^{- 12} s^{2} + 30 \cdot 1 0^{- 4} s + 820 : \frac{19}{250000000000} s^{2} + \frac{3}{1000} s + 820

\frac{19}{250000000000} s^{2} + \frac{3}{1000} s + 820 = 0

改写成标准形式

a x^{2} + b x + c = 0

\frac{19 s ^{2}}{250000000000} + \frac{3 s}{1000} + 820 = 0

使用求根公式求解

s_{1, 2} = \frac{- \frac{3}{1000} \pm ( \frac{3}{1000} ) ^{2} - 4 \cdot \frac{19}{250000000000} \cdot 820}{2 \cdot \frac{19}{250000000000}}

(\frac{3}{1000})^{2} - 4 \cdot \frac{19}{250000000000} \cdot 820 = \frac{9}{1000000} - \frac{779}{3125000000}

s_{1, 2} = \frac{- \frac{3}{1000} \pm \frac{9}{1000000} - \frac{779}{3125000000}}{2 \cdot \frac{19}{250000000000}}

将解分隔开

s_{1} = \frac{- \frac{3}{1000} + \frac{9}{1000000} - \frac{779}{3125000000}}{2 \cdot \frac{19}{250000000000}}, s_{2} = \frac{- \frac{3}{1000} - \frac{9}{1000000} - \frac{779}{3125000000}}{2 \cdot \frac{19}{250000000000}}

s = \frac{- \frac{3}{1000} + \frac{9}{1000000} - \frac{779}{3125000000}}{2 \frac{19}{250000000000}} : \frac{125000000 ( 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}

s = \frac{- \frac{3}{1000} - \frac{9}{1000000} - \frac{779}{3125000000}}{2 \frac{19}{250000000000}} : \frac{125000000 ( - 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}

二次方程组的解是:

s = \frac{125000000 ( 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}, s = \frac{125000000 ( - 1000 \frac{9}{1000000} - \frac{779}{3125000000} - 3 )}{19}

作图

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