What are the solutions to the equation 20x^2-27x=14 ?

The solutions to the equation 20x^2-27x=14 are x= 7/4 ,x=-2/5

Find the zeros of 20x^2-27x=14

The zeros of 20x^2-27x=14 are x= 7/4 ,x=-2/5

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20 x^{2} - 27 x = 14

x = \frac{7}{4}, x = - \frac{2}{5}

Decimal Notation

x = 1.75, x = - 0.4

Solution steps

20 x^{2} - 27 x = 14

Move

14

to the left side

20 x^{2} - 27 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 27 ) \pm ( - 27 ) ^{2} - 4 \cdot 20 ( - 14 )}{2 \cdot 20}

(- 27)^{2} - 4 \cdot 20 (- 14) = 43

x_{1, 2} = \frac{- ( - 27 ) \pm 43}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 27 ) + 43}{2 \cdot 20}, x_{2} = \frac{- ( - 27 ) - 43}{2 \cdot 20}

x = \frac{- ( - 27 ) + 43}{2 \cdot 20} : \frac{7}{4}

x = \frac{- ( - 27 ) - 43}{2 \cdot 20} : - \frac{2}{5}

The solutions to the quadratic equation are:

x = \frac{7}{4}, x = - \frac{2}{5}

x, x^{2} + y^{2} + z^{2} = 4

(x + 5)^{2} + (x - 2)^{2} = 37

a x^{2} + c = 0

4 x^{2} - 4 x + 3

2 x^{2} - 12 x + 16 = 0

What are the solutions to the equation 20x^2-27x=14 ?
The solutions to the equation 20x^2-27x=14 are x= 7/4 ,x=-2/5
Find the zeros of 20x^2-27x=14
The zeros of 20x^2-27x=14 are x= 7/4 ,x=-2/5