y^2-12y+35=0

解

y^{2} - 12 y + 35 = 0

y = 7, y = 5

解答ステップ

y^{2} - 12 y + 35 = 0

解くとthe二次式

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot 35 = 2

y_{1, 2} = \frac{- ( - 12 ) \pm 2}{2 \cdot 1}

解を分離する

y_{1} = \frac{- ( - 12 ) + 2}{2 \cdot 1}, y_{2} = \frac{- ( - 12 ) - 2}{2 \cdot 1}

y = \frac{- ( - 12 ) + 2}{2 \cdot 1} : 7

y = \frac{- ( - 12 ) - 2}{2 \cdot 1} : 5

二次equationの解:

y = 7, y = 5