64x^2+17=0

解

64 x^{2} + 17 = 0

x = \frac{17}{8} i, x = - \frac{17}{8} i

解答ステップ

64 x^{2} + 17 = 0

17

を右側に移動します

64 x^{2} = - 17

以下で両辺を割る

64

x^{2} = - \frac{17}{64}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = - \frac{17}{64}, x = - - \frac{17}{64}

- \frac{17}{64} = \frac{17}{8} i

- - \frac{17}{64} = - \frac{17}{8} i

x = \frac{17}{8} i, x = - \frac{17}{8} i