What are the solutions to the equation (x+9)^2=121 ?

The solutions to the equation (x+9)^2=121 are x=2,x=-20

Find the zeros of (x+9)^2=121

The zeros of (x+9)^2=121 are x=2,x=-20

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(x + 9)^{2} = 121

x = 2, x = - 20

Solution steps

(x + 9)^{2} = 121

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 9 = 121 : x = 2

Solve

x + 9 = - 121 : x = - 20

The solutions to the quadratic equation are:

x = 2, x = - 20

(x - 2)^{2} - 43 = 21

7 x^{2} = 98

2 x^{2} - 14 x = 0

- \frac{1}{2} x^{2} + 7 x = 0

2 (x^{2} - 7) - 2 = 2

What are the solutions to the equation (x+9)^2=121 ?
The solutions to the equation (x+9)^2=121 are x=2,x=-20
Find the zeros of (x+9)^2=121
The zeros of (x+9)^2=121 are x=2,x=-20