What are the solutions to the equation x^2+6x=-x+30 ?

The solutions to the equation x^2+6x=-x+30 are x=3,x=-10

Find the zeros of x^2+6x=-x+30

The zeros of x^2+6x=-x+30 are x=3,x=-10

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x^{2} + 6 x = - x + 30

x = 3, x = - 10

Solution steps

x^{2} + 6 x = - x + 30

Move

30

to the left side

x^{2} + 6 x - 30 = - x

Move

x

to the left side

x^{2} + 7 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 30) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 1}, x_{2} = \frac{- 7 - 13}{2 \cdot 1}

x = \frac{- 7 + 13}{2 \cdot 1} : 3

x = \frac{- 7 - 13}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 3, x = - 10

0 = 3 x^{2} + 6 x

x^{2} - 10 x + 2 = 0

(x - 3)^{2} + x (x + 2) = 9

3 x^{2} + 112 = 2 x^{2} + 22 x

x^{2} - 3 x + 40 = 0

What are the solutions to the equation x^2+6x=-x+30 ?
The solutions to the equation x^2+6x=-x+30 are x=3,x=-10
Find the zeros of x^2+6x=-x+30
The zeros of x^2+6x=-x+30 are x=3,x=-10