2x^2-18x+28=0

解

2 x^{2} - 18 x + 28 = 0

x = 7, x = 2

解答ステップ

2 x^{2} - 18 x + 28 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 2 \cdot 28}{2 \cdot 2}

(- 18)^{2} - 4 \cdot 2 \cdot 28 = 10

x_{1, 2} = \frac{- ( - 18 ) \pm 10}{2 \cdot 2}

解を分離する

x_{1} = \frac{- ( - 18 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 18 ) - 10}{2 \cdot 2}

x = \frac{- ( - 18 ) + 10}{2 \cdot 2} : 7

x = \frac{- ( - 18 ) - 10}{2 \cdot 2} : 2

二次equationの解:

x = 7, x = 2