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受欢迎的代数 >

2x^2+9x+3=0

解答

2 x^{2} + 9 x + 3 = 0

解答

x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

+1

十进制

x = - 0.36254 \dots, x = - 4.13745 \dots

求解步骤

2 x^{2} + 9 x + 3 = 0

使用求根公式求解

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 2 \cdot 3}{2 \cdot 2}

9^{2} - 4 \cdot 2 \cdot 3 = 57

x_{1, 2} = \frac{- 9 \pm 57}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- 9 + 57}{2 \cdot 2}, x_{2} = \frac{- 9 - 57}{2 \cdot 2}

x = \frac{- 9 + 57}{2 \cdot 2} : \frac{- 9 + 57}{4}

x = \frac{- 9 - 57}{2 \cdot 2} : \frac{- 9 - 57}{4}

二次方程组的解是:

x = \frac{- 9 + 57}{4}, x = \frac{- 9 - 57}{4}

作图

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