w^2-5w=0

解

w^{2} - 5 w = 0

w = 5, w = 0

解答ステップ

w^{2} - 5 w = 0

解くとthe二次式

w_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

w_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

解を分離する

w_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, w_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

w = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

w = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

二次equationの解:

w = 5, w = 0