What are the solutions to the equation 9x^2+6x-1=0 ?

The solutions to the equation 9x^2+6x-1=0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3

Find the zeros of 9x^2+6x-1=0

The zeros of 9x^2+6x-1=0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3

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9 x^{2} + 6 x - 1 = 0

x = \frac{- 1 + 2}{3}, x = - \frac{1 + 2}{3}

Decimal Notation

x = 0.13807 \dots, x = - 0.80473 \dots

Solution steps

9 x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 1 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 1) = 62

x_{1, 2} = \frac{- 6 \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 6 + 6 2}{2 \cdot 9}, x_{2} = \frac{- 6 - 6 2}{2 \cdot 9}

x = \frac{- 6 + 6 2}{2 \cdot 9} : \frac{- 1 + 2}{3}

x = \frac{- 6 - 6 2}{2 \cdot 9} : - \frac{1 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 1 + 2}{3}, x = - \frac{1 + 2}{3}

x^{2} - 22 x

2 y^{2} + 19 y + 24 = 0

- (x + 9)^{2} = 64

2 x - x^{2} + 3

v^{2} = 361

What are the solutions to the equation 9x^2+6x-1=0 ?
The solutions to the equation 9x^2+6x-1=0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3
Find the zeros of 9x^2+6x-1=0
The zeros of 9x^2+6x-1=0 are x=(-1+sqrt(2))/3 ,x=-(1+sqrt(2))/3