m^2-m-12=0

解

m^{2} - m - 12 = 0

m = 4, m = - 3

解答ステップ

m^{2} - m - 12 = 0

解くとthe二次式

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 12) = 7

m_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 1}

解を分離する

m_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 1}

m = \frac{- ( - 1 ) + 7}{2 \cdot 1} : 4

m = \frac{- ( - 1 ) - 7}{2 \cdot 1} : - 3

二次equationの解:

m = 4, m = - 3