t^2-4t-12=0

解

t^{2} - 4 t - 12 = 0

t = 6, t = - 2

解答ステップ

t^{2} - 4 t - 12 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 12) = 8

t_{1, 2} = \frac{- ( - 4 ) \pm 8}{2 \cdot 1}

解を分離する

t_{1} = \frac{- ( - 4 ) + 8}{2 \cdot 1}, t_{2} = \frac{- ( - 4 ) - 8}{2 \cdot 1}

t = \frac{- ( - 4 ) + 8}{2 \cdot 1} : 6

t = \frac{- ( - 4 ) - 8}{2 \cdot 1} : - 2

二次equationの解:

t = 6, t = - 2