What are the solutions to the equation completesquare 2x^2-5x-3=0 ?

The solutions to the equation completesquare 2x^2-5x-3=0 are x=3,x=-1/2

Find the zeros of completesquare 2x^2-5x-3=0

The zeros of completesquare 2x^2-5x-3=0 are x=3,x=-1/2

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2 x^{2} - 5 x - 3 = 0

x = 3, x = - \frac{1}{2}

Decimal Notation

x = 3, x = - 0.5

Solution steps

2 x^{2} - 5 x - 3 = 0

Move

3

to the right side

2 x^{2} - 5 x = 3

Divide both sides by

2

\frac{2 x ^{2} - 5 x}{2} = \frac{3}{2}

x^{2} - \frac{5 x}{2} = \frac{3}{2}

Rewrite in the form

(x + a)^{2} = b

(x - \frac{5}{4})^{2} = \frac{49}{16}

For

the solutions are

f (x) = a, - a

Solve

x - \frac{5}{4} = \frac{49}{16} : x = 3

Solve

x - \frac{5}{4} = - \frac{49}{16} : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = 3, x = - \frac{1}{2}

x^{2} + \frac{1}{2} x - 4

2 x^{2} - 3 x - 2 = 0

- x^{2} + 10 x = 16

4 x^{2} + 2 x - 12 = 0

y^{2} + y

What are the solutions to the equation completesquare 2x^2-5x-3=0 ?
The solutions to the equation completesquare 2x^2-5x-3=0 are x=3,x=-1/2
Find the zeros of completesquare 2x^2-5x-3=0
The zeros of completesquare 2x^2-5x-3=0 are x=3,x=-1/2