(4-k)x^2+2kx+2=0

Lösung

(4 - k) x^{2} + 2 k x + 2 = 0

x = \frac{- k + k ^{2} - 2 ( - k + 4 )}{4 - k}, x = - \frac{k + k ^{2} - 2 ( - k + 4 )}{- k + 4}; k \neq = 4

Schritte zur Lösung

(4 - k) x^{2} + 2 k x + 2 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 2 k \pm ( 2 k ) ^{2} - 4 ( 4 - k ) \cdot 2}{2 ( 4 - k )}

Vereinfache

(2 k)^{2} - 4 (4 - k) \cdot 2 : 2 k^{2} - 2 (4 - k)

x_{1, 2} = \frac{- 2 k \pm 2 k ^{2} - 2 ( 4 - k )}{2 ( 4 - k )}; k \neq = 4

Trenne die Lösungen

x_{1} = \frac{- 2 k + 2 k ^{2} - 2 ( 4 - k )}{2 ( 4 - k )}, x_{2} = \frac{- 2 k - 2 k ^{2} - 2 ( 4 - k )}{2 ( 4 - k )}

x = \frac{- 2 k + 2 k ^{2} - 2 ( 4 - k )}{2 ( 4 - k )} : \frac{- k + k ^{2} - 2 ( - k + 4 )}{4 - k}

x = \frac{- 2 k - 2 k ^{2} - 2 ( 4 - k )}{2 ( 4 - k )} : - \frac{k + k ^{2} - 2 ( - k + 4 )}{- k + 4}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- k + k ^{2} - 2 ( - k + 4 )}{4 - k}, x = - \frac{k + k ^{2} - 2 ( - k + 4 )}{- k + 4}; k \neq = 4

- 4 x^{2} - 8 x + 32 = 0

- \frac{3}{4} x^{2} + 8 = 0

so l v e f or x, x^{2} + y^{2} + 4 x - 4 y + 8 = 0

w^{2} - 8 = 0

a^{2} + 10 a + 18 = 9