t^2+3t-4=0

解

t^{2} + 3 t - 4 = 0

t = 1, t = - 4

解答ステップ

t^{2} + 3 t - 4 = 0

解くとthe二次式

t_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 4) = 5

t_{1, 2} = \frac{- 3 \pm 5}{2 \cdot 1}

解を分離する

t_{1} = \frac{- 3 + 5}{2 \cdot 1}, t_{2} = \frac{- 3 - 5}{2 \cdot 1}

t = \frac{- 3 + 5}{2 \cdot 1} : 1

t = \frac{- 3 - 5}{2 \cdot 1} : - 4

二次equationの解:

t = 1, t = - 4