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受欢迎的代数 >

x^2+2kx+(k-1)(k-3)=0

解答

x^{2} + 2 k x + (k - 1) (k - 3) = 0

解答

x = - k + 4 k - 3, x = - k - 4 k - 3

求解步骤

x^{2} + 2 k x + (k - 1) (k - 3) = 0

展开

x^{2} + 2 k x + (k - 1) (k - 3) : x^{2} + 2 k x + k^{2} - 4 k + 3

x^{2} + 2 k x + k^{2} - 4 k + 3 = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 k \pm ( 2 k ) ^{2} - 4 \cdot 1 \cdot ( k ^{2} - 4 k + 3 )}{2 \cdot 1}

化简

(2 k)^{2} - 4 \cdot 1 \cdot (k^{2} - 4 k + 3) : 2 - 3 + 4 k

x_{1, 2} = \frac{- 2 k \pm 2 - 3 + 4 k}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 2 k + 2 - 3 + 4 k}{2 \cdot 1}, x_{2} = \frac{- 2 k - 2 - 3 + 4 k}{2 \cdot 1}

x = \frac{- 2 k + 2 - 3 + 4 k}{2 \cdot 1} : - k + 4 k - 3

x = \frac{- 2 k - 2 - 3 + 4 k}{2 \cdot 1} : - k - 4 k - 3

二次方程组的解是:

x = - k + 4 k - 3, x = - k - 4 k - 3

作图

流行的例子

4 x^{2} - 25 x + 36 = 0

2 x^{2} - 4 x + 13 = 9

4 x (1 + x) = 0

x^2-10.24x+2.56=0

x^{2} - 10.24 x + 2.56 = 0

因式分解 x^2+10x+25=0

f a c t or x^{2} + 10 x + 25 = 0