What are the solutions to the equation 16q^2+36q=10 ?

The solutions to the equation 16q^2+36q=10 are q= 1/4 ,q=-5/2

Find the zeros of 16q^2+36q=10

The zeros of 16q^2+36q=10 are q= 1/4 ,q=-5/2

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16 q^{2} + 36 q = 10

q = \frac{1}{4}, q = - \frac{5}{2}

Decimal Notation

q = 0.25, q = - 2.5

Solution steps

16 q^{2} + 36 q = 10

Move

10

to the left side

16 q^{2} + 36 q - 10 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 16 ( - 10 )}{2 \cdot 16}

3 6^{2} - 4 \cdot 16 (- 10) = 44

q_{1, 2} = \frac{- 36 \pm 44}{2 \cdot 16}

Separate the solutions

q_{1} = \frac{- 36 + 44}{2 \cdot 16}, q_{2} = \frac{- 36 - 44}{2 \cdot 16}

q = \frac{- 36 + 44}{2 \cdot 16} : \frac{1}{4}

q = \frac{- 36 - 44}{2 \cdot 16} : - \frac{5}{2}

The solutions to the quadratic equation are:

q = \frac{1}{4}, q = - \frac{5}{2}

9 x = 3 x

\frac{12}{6 \cdot ( - 2 )}

\frac{x}{5} + 1 = - 4

\frac{64 !}{14 ! ( 64 - 14 ) !}

\frac{3}{10} + 1

What are the solutions to the equation 16q^2+36q=10 ?
The solutions to the equation 16q^2+36q=10 are q= 1/4 ,q=-5/2
Find the zeros of 16q^2+36q=10
The zeros of 16q^2+36q=10 are q= 1/4 ,q=-5/2