What are the solutions to the equation 2^2+x^2=7^2 ?

The solutions to the equation 2^2+x^2=7^2 are x=3sqrt(5),x=-3sqrt(5)

Find the zeros of 2^2+x^2=7^2

The zeros of 2^2+x^2=7^2 are x=3sqrt(5),x=-3sqrt(5)

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2^{2} + x^{2} = 7^{2}

x = 35, x = - 35

Decimal Notation

x = 6.70820 \dots, x = - 6.70820 \dots

Solution steps

2^{2} + x^{2} = 7^{2}

Move

2^{2}

to the right side

x^{2} = 45

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 45, x = - 45

45 = 35

- 45 = - 35

x = 35, x = - 35

\frac{x ^{2}}{25} + \frac{x ^{2}}{16} = 1

- 3 x^{2} - 10 x + 4 = 0

0 = x^{2} + 6 x + 11

x^{2} - 15 x - 80 = 170

5 x^{2} - 3 x + 2 = 1

What are the solutions to the equation 2^2+x^2=7^2 ?
The solutions to the equation 2^2+x^2=7^2 are x=3sqrt(5),x=-3sqrt(5)
Find the zeros of 2^2+x^2=7^2
The zeros of 2^2+x^2=7^2 are x=3sqrt(5),x=-3sqrt(5)