What are the solutions to the equation 3z^2+14z+5=0 ?

The solutions to the equation 3z^2+14z+5=0 are z=(-7+sqrt(34))/3 ,z=-(7+sqrt(34))/3

Find the zeros of 3z^2+14z+5=0

The zeros of 3z^2+14z+5=0 are z=(-7+sqrt(34))/3 ,z=-(7+sqrt(34))/3

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3 z^{2} + 14 z + 5 = 0

z = \frac{- 7 + 34}{3}, z = - \frac{7 + 34}{3}

Decimal Notation

z = - 0.38968 \dots, z = - 4.27698 \dots

Solution steps

3 z^{2} + 14 z + 5 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

1 4^{2} - 4 \cdot 3 \cdot 5 = 234

z_{1, 2} = \frac{- 14 \pm 2 34}{2 \cdot 3}

Separate the solutions

z_{1} = \frac{- 14 + 2 34}{2 \cdot 3}, z_{2} = \frac{- 14 - 2 34}{2 \cdot 3}

z = \frac{- 14 + 2 34}{2 \cdot 3} : \frac{- 7 + 34}{3}

z = \frac{- 14 - 2 34}{2 \cdot 3} : - \frac{7 + 34}{3}

The solutions to the quadratic equation are:

z = \frac{- 7 + 34}{3}, z = - \frac{7 + 34}{3}

y^{2} - 100 = 0

x^{2} + a x + 1 = 0

(x + 1)^{2} = - 121

x^{2} + 21 x + 20 = 0

x^{2} + 11 x + 5 = 0

What are the solutions to the equation 3z^2+14z+5=0 ?
The solutions to the equation 3z^2+14z+5=0 are z=(-7+sqrt(34))/3 ,z=-(7+sqrt(34))/3
Find the zeros of 3z^2+14z+5=0
The zeros of 3z^2+14z+5=0 are z=(-7+sqrt(34))/3 ,z=-(7+sqrt(34))/3