x^{(2)}+19x-42=0

解

x^{(2)} + 19 x - 42 = 0

x = 2, x = - 21

解答ステップ

x^{(2)} + 19 x - 42 = 0

改良

x^{2} + 19 x - 42 = 0

解くとthe二次式

x_{1, 2} = \frac{- 19 \pm 1 9 ^{2} - 4 \cdot 1 \cdot ( - 42 )}{2 \cdot 1}

1 9^{2} - 4 \cdot 1 \cdot (- 42) = 23

x_{1, 2} = \frac{- 19 \pm 23}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 19 + 23}{2 \cdot 1}, x_{2} = \frac{- 19 - 23}{2 \cdot 1}

x = \frac{- 19 + 23}{2 \cdot 1} : 2

x = \frac{- 19 - 23}{2 \cdot 1} : - 21

二次equationの解:

x = 2, x = - 21