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受欢迎的代数 >

a(x)=x^2+3x-10

解答

a (x) = x^{2} + 3 x - 10

解答

x = \frac{- 3 + a + a ^{2} - 6 a + 49}{2}, x = \frac{- 3 + a - a ^{2} - 6 a + 49}{2}

求解步骤

a (x) = x^{2} + 3 x - 10

整理后得

a x = x^{2} + 3 x - 10

交换两边

x^{2} + 3 x - 10 = a x

将

a x

para o lado esquerdo

x^{2} + 3 x - 10 - a x = 0

改写成标准形式

a x^{2} + b x + c = 0

x^{2} + (3 - a) x - 10 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( 3 - a ) \pm ( 3 - a ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

化简

(3 - a)^{2} - 4 \cdot 1 \cdot (- 10) : a^{2} - 6 a + 49

x_{1, 2} = \frac{- ( 3 - a ) \pm a ^{2} - 6 a + 49}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( 3 - a ) + a ^{2} - 6 a + 49}{2 \cdot 1}, x_{2} = \frac{- ( 3 - a ) - a ^{2} - 6 a + 49}{2 \cdot 1}

x = \frac{- ( 3 - a ) + a ^{2} - 6 a + 49}{2 \cdot 1} : \frac{- 3 + a + a ^{2} - 6 a + 49}{2}

x = \frac{- ( 3 - a ) - a ^{2} - 6 a + 49}{2 \cdot 1} : \frac{- 3 + a - a ^{2} - 6 a + 49}{2}

二次方程组的解是:

x = \frac{- 3 + a + a ^{2} - 6 a + 49}{2}, x = \frac{- 3 + a - a ^{2} - 6 a + 49}{2}

作图

流行的例子

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so l v e f or x, x^{2} - 3 x y = 10

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so l v e f or p, x p^{2} + (x - y) p + 1 - y = 0

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