-16x^2+240x+180=0

解

- 16 x^{2} + 240 x + 180 = 0

x = - \frac{3 ( 30 - 5 )}{2}, x = \frac{3 ( 5 + 30 )}{2}

十進法表記

x = - 0.71583 \dots, x = 15.71583 \dots

解答ステップ

- 16 x^{2} + 240 x + 180 = 0

解くとthe二次式

x_{1, 2} = \frac{- 240 \pm 24 0 ^{2} - 4 ( - 16 ) \cdot 180}{2 ( - 16 )}

24 0^{2} - 4 (- 16) \cdot 180 = 4830

x_{1, 2} = \frac{- 240 \pm 48 30}{2 ( - 16 )}

解を分離する

x_{1} = \frac{- 240 + 48 30}{2 ( - 16 )}, x_{2} = \frac{- 240 - 48 30}{2 ( - 16 )}

x = \frac{- 240 + 48 30}{2 ( - 16 )} : - \frac{3 ( 30 - 5 )}{2}

x = \frac{- 240 - 48 30}{2 ( - 16 )} : \frac{3 ( 5 + 30 )}{2}

二次equationの解:

x = - \frac{3 ( 30 - 5 )}{2}, x = \frac{3 ( 5 + 30 )}{2}