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受欢迎的代数 >

x^2-(1+a)x+a=0

解答

x^{2} - (1 + a) x + a = 0

解答

x = a, x = 1

求解步骤

x^{2} - (1 + a) x + a = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 1 - a ) \pm ( - 1 - a ) ^{2} - 4 \cdot 1 \cdot a}{2 \cdot 1}

化简

(- 1 - a)^{2} - 4 \cdot 1 \cdot a : a - 1

x_{1, 2} = \frac{- ( - 1 - a ) \pm ( a - 1 )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 1 - a ) + a - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 1 - a ) - ( a - 1 )}{2 \cdot 1}

x = \frac{- ( - 1 - a ) + a - 1}{2 \cdot 1} : a

x = \frac{- ( - 1 - a ) - ( a - 1 )}{2 \cdot 1} : 1

二次方程组的解是:

x = a, x = 1

作图

流行的例子

19 x^{2} = 19 x

x^{2} - \frac{x}{2} = \frac{3}{10}

4 x^{2} + 8 x - 2 = 0

solvefor v,F=(mv^2)/t

so l v e f or v, F = \frac{m v ^{2}}{t}

x^{2} + 3 x - 30 = 0