What are the solutions to the equation 0=3x^2-18x+24 ?

The solutions to the equation 0=3x^2-18x+24 are x=4,x=2

Find the zeros of 0=3x^2-18x+24

The zeros of 0=3x^2-18x+24 are x=4,x=2

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0 = 3 x^{2} - 18 x + 24

x = 4, x = 2

Solution steps

0 = 3 x^{2} - 18 x + 24

Switch sides

3 x^{2} - 18 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 3 \cdot 24}{2 \cdot 3}

(- 18)^{2} - 4 \cdot 3 \cdot 24 = 6

x_{1, 2} = \frac{- ( - 18 ) \pm 6}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6}{2 \cdot 3}, x_{2} = \frac{- ( - 18 ) - 6}{2 \cdot 3}

x = \frac{- ( - 18 ) + 6}{2 \cdot 3} : 4

x = \frac{- ( - 18 ) - 6}{2 \cdot 3} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

3 s^{2} + 2 s + 1 = 0

4 x^{2} - 12 x - (x + 5)^{2} = - 32

25 - 2 x^{2} = 0

(x + 1)^{2} - 3 = 0

x^{2} - 200 x + 9600 = 0

What are the solutions to the equation 0=3x^2-18x+24 ?
The solutions to the equation 0=3x^2-18x+24 are x=4,x=2
Find the zeros of 0=3x^2-18x+24
The zeros of 0=3x^2-18x+24 are x=4,x=2