What are the solutions to the equation k^2=6k ?

The solutions to the equation k^2=6k are k=6,k=0

Find the zeros of k^2=6k

The zeros of k^2=6k are k=6,k=0

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k^{2} = 6 k

k = 6, k = 0

Solution steps

k^{2} = 6 k

Move

6 k

to the left side

k^{2} - 6 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

k_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, k_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

k = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

k = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 6, k = 0

x^{2} - 20 = 5

\frac{( - 5 - 3 ) ^{2}}{9} - \frac{( y - 4 ) ^{2}}{4} = 1

c, e = m \cdot c^{2}

28 = y^{2}

0 = x^{2} - 6 x + 7

What are the solutions to the equation k^2=6k ?
The solutions to the equation k^2=6k are k=6,k=0
Find the zeros of k^2=6k
The zeros of k^2=6k are k=6,k=0