b^2-16b+64=0

解

b^{2} - 16 b + 64 = 0

b = 8

解答ステップ

b^{2} - 16 b + 64 = 0

解くとthe二次式

b_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

b_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

b = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

b = 8

二次equationの解:

b = 8