-x^2+2x+7=0

Lösung

- x^{2} + 2 x + 7 = 0

x = 1 - 22, x = 1 + 22

Dezimale

x = - 1.82842 \dots, x = 3.82842 \dots

Schritte zur Lösung

- x^{2} + 2 x + 7 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 7}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 7 = 42

x_{1, 2} = \frac{- 2 \pm 4 2}{2 ( - 1 )}

Trenne die Lösungen

x_{1} = \frac{- 2 + 4 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 4 2}{2 ( - 1 )}

x = \frac{- 2 + 4 2}{2 ( - 1 )} : 1 - 22

x = \frac{- 2 - 4 2}{2 ( - 1 )} : 1 + 22

Die Lösungen für die quadratische Gleichung sind:

x = 1 - 22, x = 1 + 22

\frac{x ^{2}}{3} - \frac{x ( x - 1 )}{4} - 1 = (x^{2} - 1)

3 x^{2} - 1 = 4 λ x, - y = 2 λ x, x^{2} + y^{2} = 1

x^{2} + 2 x + 7 = x + 7

- x^{2} + 2 x + 9 = 0

d^{2} = 50 - 23 d