What are the solutions to the equation 3t^2-10t+4=0 ?

The solutions to the equation 3t^2-10t+4=0 are t=(5+sqrt(13))/3 ,t=(5-sqrt(13))/3

Find the zeros of 3t^2-10t+4=0

The zeros of 3t^2-10t+4=0 are t=(5+sqrt(13))/3 ,t=(5-sqrt(13))/3

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3 t^{2} - 10 t + 4 = 0

t = \frac{5 + 13}{3}, t = \frac{5 - 13}{3}

Decimal Notation

t = 2.86851 \dots, t = 0.46481 \dots

Solution steps

3 t^{2} - 10 t + 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 10)^{2} - 4 \cdot 3 \cdot 4 = 213

t_{1, 2} = \frac{- ( - 10 ) \pm 2 13}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 10 ) + 2 13}{2 \cdot 3}, t_{2} = \frac{- ( - 10 ) - 2 13}{2 \cdot 3}

t = \frac{- ( - 10 ) + 2 13}{2 \cdot 3} : \frac{5 + 13}{3}

t = \frac{- ( - 10 ) - 2 13}{2 \cdot 3} : \frac{5 - 13}{3}

The solutions to the quadratic equation are:

t = \frac{5 + 13}{3}, t = \frac{5 - 13}{3}

3 x^{2} = - 7 x

- 3 (p + 2)^{2} = 12

x^{2} = 24 - 4 x

(x - 12) (x - 6) = 27

- 16 t^{2} + 80 t + 60 = 0

What are the solutions to the equation 3t^2-10t+4=0 ?
The solutions to the equation 3t^2-10t+4=0 are t=(5+sqrt(13))/3 ,t=(5-sqrt(13))/3
Find the zeros of 3t^2-10t+4=0
The zeros of 3t^2-10t+4=0 are t=(5+sqrt(13))/3 ,t=(5-sqrt(13))/3