What are the solutions to the equation x^2+3x+3=10 ?

The solutions to the equation x^2+3x+3=10 are x=(-3+sqrt(37))/2 ,x=(-3-sqrt(37))/2

Find the zeros of x^2+3x+3=10

The zeros of x^2+3x+3=10 are x=(-3+sqrt(37))/2 ,x=(-3-sqrt(37))/2

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x^{2} + 3 x + 3 = 10

x = \frac{- 3 + 37}{2}, x = \frac{- 3 - 37}{2}

Decimal Notation

x = 1.54138 \dots, x = - 4.54138 \dots

Solution steps

x^{2} + 3 x + 3 = 10

Move

10

to the left side

x^{2} + 3 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 7) = 37

x_{1, 2} = \frac{- 3 \pm 37}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 37}{2 \cdot 1}, x_{2} = \frac{- 3 - 37}{2 \cdot 1}

x = \frac{- 3 + 37}{2 \cdot 1} : \frac{- 3 + 37}{2}

x = \frac{- 3 - 37}{2 \cdot 1} : \frac{- 3 - 37}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 37}{2}, x = \frac{- 3 - 37}{2}

x (x + 2)^{2} = (x + 1)^{3} + 5

x^{2} + 2 x + 4 = 0

x, (x - 1)^{2} + (y - 2)^{2} = 0

A = x^{2} + 6 x + 5

4 (x + 3)^{2} + 9 = - 29

What are the solutions to the equation x^2+3x+3=10 ?
The solutions to the equation x^2+3x+3=10 are x=(-3+sqrt(37))/2 ,x=(-3-sqrt(37))/2
Find the zeros of x^2+3x+3=10
The zeros of x^2+3x+3=10 are x=(-3+sqrt(37))/2 ,x=(-3-sqrt(37))/2