zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

0=100+10t-(1.62)/2 t^2

解答

0 = 100 + 10 t - \frac{1.62}{2} t^{2}

解答

t = - \frac{- 20 + 4 106}{3.24}, t = \frac{20 + 4 106}{3.24}

+1

十进制

t = - 6.53781 \dots, t = 18.88349 \dots

求解步骤

0 = 100 + 10 t - \frac{1.62}{2} t^{2}

在两边乘以

2

0 = 200 + 20 t - 1.62 t^{2}

交换两边

200 + 20 t - 1.62 t^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

- 1.62 t^{2} + 20 t + 200 = 0

使用求根公式求解

t_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 1.62 ) \cdot 200}{2 ( - 1.62 )}

2 0^{2} - 4 (- 1.62) \cdot 200 = 4106

t_{1, 2} = \frac{- 20 \pm 4 106}{2 ( - 1.62 )}

将解分隔开

t_{1} = \frac{- 20 + 4 106}{2 ( - 1.62 )}, t_{2} = \frac{- 20 - 4 106}{2 ( - 1.62 )}

t = \frac{- 20 + 4 106}{2 ( - 1.62 )} : - \frac{- 20 + 4 106}{3.24}

t = \frac{- 20 - 4 106}{2 ( - 1.62 )} : \frac{20 + 4 106}{3.24}

二次方程组的解是:

t = - \frac{- 20 + 4 106}{3.24}, t = \frac{20 + 4 106}{3.24}

作图

流行的例子

solvefor q,3+q^2= G/R

so l v e f or q, 3 + q^{2} = \frac{G}{R}

10 x^{2} - 5 = - 20

p^{2} - 1 = 0

completesquare x^2+8x+13=0

co m pl e t es q u a re x^{2} + 8 x + 13 = 0

x^{2} + 3 x + 54 = 0