solvefor t,8left(x-2)left(x+2/5)^2=0

解

解く

t, 8 l e f t (x - 2) l e f t (x + \frac{2}{5})^{2} = 0

t = 0; l \neq = 0

解答ステップ

8 l e f t (x - 2) l e f t (x + \frac{2}{5})^{2} = 0

簡素化

8 e^{2} l^{2} t^{2} f^{2} (x - 2) (x + \frac{2}{5})^{2} = 0

以下で両辺を割る

8 e^{2} l^{2} f^{2} (x - 2) (x + \frac{2}{5})^{2}; l \neq = 0

\frac{8 e ^{2} l ^{2} t ^{2} f ^{2} ( x - 2 ) ( x + \frac{2}{5} ) ^{2}}{8 e ^{2} l ^{2} f ^{2} ( x - 2 ) ( x + \frac{2}{5} ) ^{2}} = \frac{0}{8 e ^{2} l ^{2} f ^{2} ( x - 2 ) ( x + \frac{2}{5} ) ^{2}}; l \neq = 0

t^{2} = 0; l \neq = 0

規則を適用

x^{n} = 0 \Rightarrow x = 0

t = 0; l \neq = 0